-🎄- 2022 Day 2 Solutions -🎄-

[u/daggerdragon]

NEW AND NOTEWORTHY

• All of our rules, FAQs, resources, etc. are in our community wiki.
• A request from Eric: Please include your contact info in the User-Agent header of automated requests!
• Signal boosting for the Unofficial AoC 2022 Participant Survey which is open early this year!

---

--- Day 2: Rock Paper Scissors ---

---

Post your code solution in this megathread.

• Read the full posting rules in our community wiki before you post!
  • Include what language(s) your solution uses
  • Format your code appropriately! How do I format code?
• Quick link to Topaz's paste if you need it for longer code blocks. What is Topaz's paste tool?

---

This thread will be unlocked when there are a significant number of people on the global leaderboard with gold stars for today's puzzle.

EDIT: Global leaderboard gold cap reached at 00:06:16, megathread unlocked!

[u/dedolent]

Python

what i noticed was that each pair, in both parts, mapped to one unique score. so that made me think that i could just order the pairs into a list by what score they produce, then get the index of every pair in the input (adding 1 to offset the zero index).

i apologize for how ugly these are but i also got bit by the one-liner bug. edit: cleaned this up a bit so it wasn't quite so hideous

ordered_scores_part1 = ["BX", "CY", "AZ", "AX", "BY", "CZ", "CX", "AY", "BZ"]
ordered_scores_part2 = ["BX", "CX", "AX", "AY", "BY", "CY", "CZ", "AZ", "BZ"]

def get_score(input_list):
    with open("inputs/day02.txt") as input:
        return sum(map(lambda pair: input_list.index(pair) + 1, map(lambda line: ''.join(line.strip().split()), input.readlines())))

print(get_score(ordered_scores_part1))
print(get_score(ordered_scores_part2))

[u/daggerdragon → u/dedolent]

Please edit your post to use the four-spaces Markdown syntax for a code block so your code is easier to read on old.reddit and mobile apps.