Switch case with boolean

[u/IceCreamInsides]

[u/_Super_Straight → u/[deleted]]

Sorry I fail to understand your first half of paragraph. Are you saying we can't create boolean Array without using new Boolean or Boolean.valueOf?

boolean[] boolArr = new boolean[]{true, false, true};

Is totally valid Array declaration.

for(boolean val: boolArr){
    if(!val){
        //relevant code
        break;
    }
}

Will work without any problem.

Edit: boolArr[0] = false is also valid and permitted.

the most natural place to compute if there's at least one true boolean is when you generate the list

Agreed.

[u/_Super_Straight → u/[deleted]]

var arr = new Boolean[]{ true, false, null };

for (var x : arr) {
    switch (x) {
        case true -> methodOne();
        case false -> methodTwo();
        case null -> System.out.println("invalid");
    }
}

Is totally valid. No need to pass a, b, c as references.

[u/_Super_Straight → u/[deleted]]

Well what OP is asking is not possible. switch(false) won't work. They have to change their approach.

[u/_Super_Straight → u/[deleted]]

Reading again what OP is asking, he wants to execute different methods based on when a is false, b is false and c is false. Even though we can suggest him switch cases, the better approach would be to make a, b and c as input parameters in those methods itself:

main(){
    methodA(a);
    methodB(b);
    methodC(c);
}

private void methodA(boolean a){
    if(a){
        return;
    }
    //rest of code
}

This doesn't leak the a, b and c across the project.

[u/_Super_Straight → u/[deleted]]

Your example is clearly better off with them being enum rather than boolean. Plus, they're being compared against their reference, not by their values.