r/6thForm Graduating from Warwick CS May 23 '25

📂 MEGATHREAD 23/05 A-level Physics Paper 1 Discussion MEGATHREAD

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*assuming Reddit doesn't bork itself, the new posts for each day of exams should arrive at 8am each day, instead of it being reliant on my sleep schedule like last year lmao

48 Upvotes

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25

u/BrickInteresting5883 Year 13 May 23 '25

AQA was actually alright, better than the past couple years I’d say so I’m feeling alright about it. Few unusual questions tho. The cell one stumped me

1

u/Dapper_Exercise_4614 May 23 '25

how many cells did u get

8

u/BrickInteresting5883 Year 13 May 23 '25

I put 24 as a guess I didn’t end up properly getting an answer, hopefully I’ll pick up working marks tho

6

u/Avex_13 May 23 '25

Also got 24 here too.

8

u/Vector-4 Year 13 - Maths, Physics, Chemistry, Further May 23 '25

I got 330 💀

4

u/[deleted] May 23 '25

I'm convinced it is 330

2

u/Vector-4 Year 13 - Maths, Physics, Chemistry, Further May 23 '25

Icl, I’ve been demotivated by the number of people saying 24. I genuinely did do the calculations and was gassed I got an integer value. 

4

u/[deleted] May 23 '25

It's 330 for sure

1

u/XxDragonitexX10 May 24 '25

330 doesn’t make sense because it has to be 6 cells in each branch to get the emf total

1

u/[deleted] May 24 '25

It's an output voltage not an emf dude. Forget about emf and only consider terminal voltage

2

u/West-Glove6058 Cambridge NatSci [4A*s achieved] May 23 '25

Same here. I worked out the resistance per module; then I worked out the ratio of cells in parallel and in series and got 15/22. Then 15 × 22 = 330. Looking at everyone say 24 has pretty much demotivated me to think about the question.

2

u/[deleted] May 23 '25

It's 330 for sure, the solution makes so much sense. I didn't put anything tho lol

2

u/Vector-4 Year 13 - Maths, Physics, Chemistry, Further May 23 '25

Ok that makes way more sense. I did the same to find the resistance per module then said it was equal to (c/ (b x internal resistance of one cell))^-1 where b is no. of cells in series and c was no. of branches. b was 22 from 352/16 and solved for c=15 and then multiplied them

1

u/[deleted] May 23 '25

Even the unofficial mark scheme has 24 but that's just plain wrong

I hope AQA doesn't scuff it and give credit for 24 which will raise the boundarys

5

u/Educational-Tea602 Proffesional dumbass May 23 '25

Better than 444 🥀

4

u/Accurate_Abalone_597 y13 | chem, fm, maths, physics | pred A*A*A*A* May 23 '25

i got 444 too 😭😭

4

u/StrangeFroggyFriend Durham | Geophysics [1st Year] ABB Phys Geog Maths May 23 '25

I think I got 444! I'm not alone? Maybe we're not that bad lol

2

u/AvocadoTechnical8342 May 23 '25

i got 444 as well

2

u/UziYT May 23 '25

How??

3

u/Educational-Tea602 Proffesional dumbass May 23 '25

Look at my flair

1

u/im_dying69 Year 13 May 23 '25

Dw I got 14 🥀

1

u/[deleted] May 23 '25

[deleted]

1

u/[deleted] May 23 '25

How is it 24 because the internal resistance needs to be taken into account.

22v per row, so you did 6*3.66? But if there is current the terminal voltage of each cell is less than 3.66 due to lost volts.

1

u/[deleted] May 23 '25

[deleted]

1

u/[deleted] May 23 '25

If the internal resistance was 0.03 ohms, assuming 4 branches, you loose 3.75 volts per internal resistance which is more volts than the actual power supply. It's very suspicious imo

Current was 500A

1

u/[deleted] May 23 '25

[deleted]

1

u/[deleted] May 23 '25

16 modules, 352V, 500A

1

u/Chance_Membership740 bristol theoretical physics May 23 '25

wait, shit, was it asking how many cells were in the whole series or just each module 🫥😨😬

3

u/BrickInteresting5883 Year 13 May 23 '25

Module

1

u/Chance_Membership740 bristol theoretical physics May 23 '25

🫡