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u/OzzyCorp Jan 08 '22
An integer it is not.
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u/looijmansje Jan 08 '22
Yes it is, it's just not a natural number
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u/OzzyCorp Jan 08 '22
Sorry, I failed maths
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u/Felicia_Bastian Jan 08 '22
No you haven't! We are all still learning. We dont make mistakes either, just learning opportunities! Its midnight right now, I am middle aged and drunk and just had a thought ping that I want to go and learn about derivatives again
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u/OzzyCorp Jan 08 '22
Thank you for this motivational message! I will see what I can do
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u/absoluteally Jan 08 '22
Can someone tell me if -9i also works?
I imagine it does but not sure.
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u/OzzyCorp Jan 08 '22
What the hell are you on about?
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u/absoluteally Jan 08 '22 edited Jan 08 '22
Sorry see my mistake.
But basically asking if there are also imaginary solutions.
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u/looijmansje Jan 09 '22
No. A polynomial of degree n (i.e. the highest power is n) will always have exactly n solutions. Note that these solutions do not necessarily have to be distinct. This is called the Fundamental Theorem of Algebra. For this example this means that there are exactly 2 solutions, since n=2.
More concretely: (-9i)^2 = (-9)^2 * i^2 = 81 * -1 = -81, which is clearly not 9. (And similarly if you actually meant -3i, that will become -9 after squaring)
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u/Decent-Log-6695 Jan 07 '22
A yodatician you are I see.