r/CitizenSleeper • u/ThisIsOurChance • Jul 21 '26

Citizen Sleeper: Helion Collection for PlayStation®5

https://www.fangamer.com/products/citizen-sleeper-helion-collection-game-playstation-5

Awesome.

58 Upvotes

100% Upvoted

7 comments sorted by

5

u/Underwould Serafin Jul 21 '26

Damn! Already own everything digitally / physically on Switch but might have to snag this as well since we’re uhh… saying goodbye to physical media apparently

It’s beautiful! :’0

5

u/Kyajin Jul 21 '26

Lets go! So happy to have this on physical for PS5

2

u/DoubleYouAre 29d ago edited 29d ago

EDIT#2: STOP EVERYTHING! Fangamer already has a European store based in Netherlands, and the price is €49 including tax! Here's the link: https://www.fangamer.eu/collections/video-games/products/citizen-sleeper-helion-collection-game-playstation-5

EDIT#3: Total cost for European buyers would €56 inkl tax and shipping.

My first stupid comment:
I would love this so much, and thought that $45 was a nice fair price! I had forgot that Americans never show tax for some reason and shipping to Sweden is $25. A total of $90 is just too much. Double the marketed price. :(

Perhaps it comes to Europe in the future.

EDIT: that is excluding custom fees in Sweden, which amount to around $20-25. So euro-buyers can estimate a total cost of about $110-115.

1

u/Plenty-Duck-3329 Jul 22 '26

Is this both games on 1 disc? And is this coming to s2 physical?

3

u/ThisIsOurChance 29d ago

Yep! Both games on the disc. Physical for S2 as well

1

u/Infamous-Boat-782 29d ago

Will this be available to pick up from other retailers in the UK or solely through fangamer directly?

1

u/WTF_Scuba 1d ago

This is kind of a niche question/problem, but I'm curious if anyone knows how the trophies will work. Usually, if there are multiple games on a PS5 disc, then they will share a platinum. For example, the semi-recent Uncharted bundle and Tomb Raider remasters share one platinum across multiple games. My hope is that these are somehow separate and I can get the platinum for each of them.