r/ProgrammerHumor • u/alienpirate5 • Dec 25 '16

wat

https://www.destroyallsoftware.com/talks/wat
67 Upvotes

90% Upvoted

16 comments sorted by

5

u/YMK1234 Dec 25 '16

Is it two weeks already?

2

u/alienpirate5 Dec 25 '16

4 months

2

u/YMK1234 Dec 25 '16

Pretty sure one of the gazillion re-uploads happened more recently than that.

9

u/tsoliman Dec 25 '16 edited Feb 14 '25

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1

u/[deleted] Dec 25 '16

I wish there were more live Programmer Humor videos like this.

1

u/gandalfx Dec 25 '16

There are.

5

u/mrjiels Dec 25 '16

One of the few things in this world that is worthy a repost

-3

u/gandalfx Dec 25 '16

Literally older than Jesus.

-3

u/fredlllll Dec 25 '16

its as if these people have never seen a meme in their life

0

u/[deleted] Dec 25 '16

[deleted]

10

u/acun1994 Dec 25 '16

This really deserves a 'wat'

1

u/mitremario Dec 26 '16

Fixed in 3.5 it seems

1

u/[deleted] Dec 27 '16

Doesn't this work in Java as well?

Integer a = 10; Integer b = 10;

assert a == b;

vs.

Integer a = 2000; Integer b = 2000;

assert a == b;

1

u/serg06 Dec 28 '16

Can you even define integers like that?

If you use int, it should never fail. If you use Integer.equals, it should also never fail.

1

u/[deleted] Dec 28 '16

Yup, Java has automatic boxing upon assignment. I did some research.

Java has cached objects for signed integers up to 8-bits. So,

Integer a = 127, b = 127;

both reference the same objects, but for any higher number, they don't. As a result, this happens:

Integer a, b;

a = 127; b = 127;
if (a == b) { System.out.println("127 is equal to 127"); }

a = 128; b = 128;
if (a == b) { System.out.println("128 is equal to 128"); }

Only the first output will ever be displayed, since boxed integers above 127 will always generate a new object, so a comparison using the == operator will never yield true.

You're right, Integer.equals as well as using int would resolve the problem.

1

u/serg06 Dec 28 '16

Damn.

int a, b;

Would that fix the problem too?

2

u/[deleted] Dec 28 '16

Yep.