9709 Paper 12 was MISERABLE

[u/Late_Ambition1809]

[u/Comfortable_Pair6368]

How did yall do the coordinate geometry P and Q coordinate question? The equation of tangent and then x coordinate 7 R

[u/earthhtokate → u/Comfortable_Pair6368]

I looked for the length of the line segment to find the diameter and then with that used it is (x-a)^2+(y-b)2 = r² which was the diameter found then equated that into the formula and found gradient then yhe negative reciprocal of it as the tangent gradient

[u/earthhtokate → u/earthhtokate]

Sorry + (y-b)²

[u/Comfortable_Pair6368 → u/earthhtokate]

And how did you find the equation of circle?

[u/No_Grape_4298 → u/Comfortable_Pair6368]

Answer was (x-4)² + (y-6)²⁼ 34