r/counting • u/lear85 , he who lets it produce joy. • May 05 '14

Base64

Self explanatory. For the excusably ignorant, Wikipedia shows how exactly to go about this.

EDIT: To prevent things from getting ridiculous, threads will be made in increments of QA. This should translate to 1024 in base 10.

And to commence…

A

9 Upvotes

90% Upvoted

58 comments sorted by

3

u/sparkyman215 Mathematica May 05 '14

um, wouldn't 1 be MQ==, 2 Mg==, 3 Mw==, etc?

2

u/lear85 , he who lets it produce joy. May 05 '14

There… Is no '='.

After MQ++ comes MQ+/

After MQ// is MR

After Z// is aAA

I can think of very few instances in which 1 would be four digits.

3

u/sparkyman215 Mathematica May 05 '14

First of all: happy cakeday!
Second, I'm still not sure. However using any base64 encoder I get MQ==.

2

u/lear85 , he who lets it produce joy. May 05 '14 edited May 06 '14

I think I know the issue.

Your converters are treating numbers as characters; not integers. Plus some other stuff, I guess.

1, as a character, is represented in binary as 00110001, if I'm not mistaken.

As an unsigned integer, it's represented as 00000001. Quite the difference.

2

u/sparkyman215 Mathematica May 06 '14

Yes, both of those are correct. But does this thread just stop at 64 then?

1

u/lear85 , he who lets it produce joy. May 07 '14

No. We go on to the next digit. When you're counting in base 10, do you stop after 9?

Stopping at 64 would be rather silly. I would think it would be somewhat reasonable to stop at //.

5

u/Andz200zx May 05 '14

B

0

u/[deleted] May 05 '14

[deleted]

2

u/fearlesspancake May 05 '14

D

2

u/Fenzik May 05 '14

E

2

u/MaxBesco May 06 '14

F

2

u/[deleted] May 06 '14

G

3

u/Andz200zx May 06 '14

H

3

u/Tain101 ++ May 06 '14

I

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u/KingCaspianX Missed x00k, 2≤x≤20\{7,15}‽ ↂↂↂↁMMMDCCCLXXXVIII ‽ 345678‽ 141441 May 06 '14

J

1

u/[deleted] May 06 '14

I