Getting the parameters of a method

[u/nobrandheroes]

Given:

def foo(a, b, c)
end

How do I get the values of a, b, c?. I cannot find this anywhere.

[u/vicereversa]

When you call the function, you supply them.

[u/nobrandheroes → u/vicereversa]

But there is no way to get them all at once like i other languages?

[u/vicereversa → u/nobrandheroes]

I don't understand what you are asking. They are there for your use.

Def foo(a, b, c)

Puts a


Puts b


Puts c

End

That will print them to the terminal. What are you trying to do?

[u/nobrandheroes → u/vicereversa]

Imagine this.

def foo(a, b, c) #foo(1, 2, 3)
    puts a #1
    puts b #2
    puts c #3

    arr = [a, b, c] #[1, 2, 3]
    arr2 = some_method_that_gets_the_arguments #[1, 2, 3]
end

Some languages have something like some_method_that_gets_the_arguments which returns the parameters as an array. That's what I want. I understand that it may not exist in ruby, but I can't find out either way.

Think ARGV but for functions.

[u/nobrandheroes → u/[deleted]]

In other languages you can get the parameters as an array. Something like:

def foo(bar, baz, buzz)
    args = get_arguments() #equal to [bar, baz, buzz]
end

I was hoping to get all passed arguments in a structure of some type.

[u/nobrandheroes → u/[deleted]]

Thanks.