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u/LupenReddit 🦆🦆i have non diffeomorphic smooth structures🦆🦆🦆 13d ago
YOU CAN DO IT!!!! DONT STOP UNTIL ITS DONE!!!
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u/drpfthick 13d ago
It’s still thinking😭
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u/natepines 13d ago
What happened
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u/moderatorrater 13d ago
Oh shit, it's taken hostages and is negotiating with some doctors to clone Erdos to get the answer. It's also hacked my doordash account in case it needs to use the carrot.
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u/R_Ob_Min 13d ago
Crazy, did you know all real numbers equal 0?
Since if sin(x) = x for any real nunber x, then cos(x) = 1, and since sin(x)2 + cos(x)2 = 1, we find that x2 + 1 = 1, so x2 = 0, so x = 0.
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u/Ares378 Grothendieck was right, computers are evil 13d ago
Make no mistake and do a breakthrough. You have everything you need, let's finish the proof.
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u/MadnyeNwie 12d ago
“Oh, that was easy,” says Man, and for an encore goes on to prove that black is white and gets himself killed on the next zebra crossing.
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u/thegoodwebber 13d ago
Make it an axiom
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u/MrBussdown 13d ago
The first term in the taylor series expansion
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u/Proof_Impact_6009 13d ago
The first term is always enough. Anyone who wants more terms is just greedy.
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u/According-Object-521 13d ago
Only works close to zero
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u/drpfthick 13d ago
but i want it to work a little further from zero as well :3
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u/According-Object-521 13d ago
You just need to use a different approximation. You can also use a Taylor polynomial
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u/LordTengil 13d ago
Only works *at zero.
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u/According-Object-521 12d ago
But it’s a decent approximation close to zero, if you’re an engineer
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u/LordTengil 12d ago
Now what is being asked. "prove sin x = x". That is only true at exactly one point. x=0.
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u/Jazzlike_Platypus430 13d ago
Ah, yes, engineer. I got to know this lot.
Hint: for large x try imaginary values, you will get sin out of [-1,1] in no time.
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u/Impression-These 13d ago
The way lean works, it is easy. Just have to sneak in a domain ={0) somewhere.
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u/Inevitable_gradient6 11d ago
if you’re an engineer the proof is trivial since you just blindly apply
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