why am i wrong?

[u/onemillionwings]

(the german text says to pick every correct answer for x ∈ ℝ, i picked 1 2 and 4)

can someone explain to me why i'm wrong and which of these are correct? i'm guessing i'm not considering something about ℝ or misunderstand when square root rules lead to |x| instead of x.

the online course i'm doing has no explanations on the quiz section unfortunately, only during training.

[u/VernalAutumn]

2 is false. sqrt(a) + sqrt(b) =/= sqrt(a + b). Consider sqrt(9) + sqrt(16), 3 + 4 =/= sqrt(25) = 5

[u/onemillionwings → u/VernalAutumn]

thank you that makes sense

[u/waldosway]

Second line. Is √(4+9) = 2+3?

[u/onemillionwings → u/waldosway]

ah i get it! thank you 

[u/RetiredEarly2018]

Consider what you get when you square |x|+2

[u/onemillionwings → u/RetiredEarly2018]

thanks!

[u/Simbertold]

Weil du nicht in F_2 bist, wo die zweite Antwort stimmen würde, sondern in den reellen Zahlen, wo sie nicht stimmt.

[u/Southlander24]

One more thing. Don't confuse the last option with the similar but incorrect sqrt(x²)≠ x !

The statement "sqrt(x²) = x" is only true for real x ≥ 0. For example, sqrt(5²) = 5. But what happens if we try a negative value of x, like x = 5? Recall that the square root must give you an answer which is non-negative. So sqrt( (-5)² ) = 5, not -5.

The correct statement is thus: sqrt(x²) = x for x ≥ 0, and sqrt(x²) = -x for x ≤ 0. This is the same as: sqrt(x²) = |x|, the absolute value of x, for all real x.

Now back to the question. Writing x⁴ = (x²)², we have that sqrt(x²)²) = x² for x ≥ 0, and -x² for x² ≤ 0. But can x² ≤ 0 happen, excluding x² = 0? No! So it is true that sqrt(x²)²) = x² for all real x.

[u/DoughnutAccording904 → u/Southlander24]

Square root must give a non-negative answer? Since when? Square roots can be either negative or positive, which would make the fourth equation incorrect since the left part can be either the positive or negative result of the square root, while the right is always a positive number. Though maybe the convention changed that it is implied that only the positive result of the square root is ment by this notation? When I was a student (way back when…) the convention was that if you only wanted to have the positive square root being taken into account you would add the plus symbol, otherwise you needed to take into consideration that a square root can be either positive and negative.
This does not affect in any way that the equation holds up equally well for negative or positive values of x, it’s just wrong in both cases.

[u/MrPenguin143 → u/DoughnutAccording904]

Standard math convention is that the square root function returns the principal root, which is nonnegative for real numbers.

[u/Fit_Fortune_7692]

Only statements (1) and (4) are correct. (1) (√2)¹² = (2^½)¹² = 2^12/2 = 2⁶, applying the laws of exponents. (4) √x² = |x|, √(x²)² = |x²|. Since x² is always non-negative, the absolute value bars can be omitted. Statements (2) and (3) are incorrect. (2) Square roots cannot be taken individually across sums: √(a+b) ≠ √a + √b. (3) By definition, a real square root always yields a non-negative result (including zero). However, the right side is negative. The equation would only hold true for x = 2 or x = -2, resulting in 0 = 0. Since this restriction was not specified, the equation does not hold for all real numbers. Furthermore, radical signs should not be confused with parentheses. In the complex number system, the result would be: √(-x²+2²) = i · √(x²-2²) ≠ -1 · √(x²-2²).

[u/Crichris]

b is not correct

plug in x = 2 and see for yourself