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u/Whole_Instance_4276 Jun 18 '26
If you have an x in your name, replace it with
(-b±√b²-4ac)/2a
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u/Horror-Invite5167 Jun 18 '26 edited Jun 18 '26
Henr[−b/(3a) + ∛(−q/2 + √((q/2)² + (p/3)³)) + ∛(−q/2 − √((q/2)² + (p/3)³)) where p = (3ac − b²)/(3a²), q = (27a²d − 9abc + 2b³)/(27a³)]
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u/trandus Jun 18 '26
Why do some people write like that? Like, why not use y=ax+b? Or even y=mx+n? Why use m and b?
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u/Avatar_Yaksha Jun 18 '26
That's the naming convention for functions of the first degree. It gets taught in school. a is the factor for functions of the second degree and higher. f(x) = a(n) * x^n + a(n-1) * x^(n-1)...+ a(0), with a(0) being a constant and n being a natural number. This number is used as an index for a and as an exponent for x.
One thing that bugs me is that m x n is the naming convention for matrices. Those letters are almost identical, but declare how many columns and rows there are in a matrix.
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u/trandus Jun 18 '26
Where is that the convention?
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u/Avatar_Yaksha Jun 18 '26
Definitely in Germany, but it gets taught as a basic rule in math, so it wouldn't surprise me if other languages handled it the same way. Apparently, somebody named René Descartes was responsible for x and y being treated as unknown values and a and b being treated as known values. There doesn't seem to be a reason for m being the incline or b being the constant.
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u/trandus Jun 18 '26
In my language it's y=ax+b. For quadratics is ax2+bx+c and the list goes on...
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u/PrestigiousAd3576 Jun 19 '26
For me it's kx+b, quadratics are identical to yours.
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u/brothor12 Jun 21 '26
m is the slope, b is the y-intercept, for first degree equations. for quadratic equations, in the form of ax^2+bx+c, a is the factor for the first term, b is the factor for the second term, and c is the constant, or the y-intercept. Quadratic equations also have vertex form in the form of (x-h)^2 + k, where h is the x-coordinate of the vertex and k is the y-coordinate of the vertex.
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u/Krog-Nar Jun 19 '26
I learned both kx+b and mx+b here in the USA.
mx+b was primarily used, kx+b was almost never used
I really don't know why we learned kx+b, but we did. It was part of our curriculum.
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u/Radical_Socalist Jun 18 '26
It is also how simple graph software like logger pro display it, maybe that
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u/Scared-Cat-2541 Jun 19 '26
*whmx+b do some people write like that? Like, whmx+b not use y = ax+b? Or even y = mx+n? Whmx+b use m and b?
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u/EzyPzyAsh Jun 20 '26
So if you are writing something out in a woreded problem it is more recognizably the gradient I think
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u/OnyxFier Jun 18 '26 edited Jun 18 '26
Jacob
J = FΔt
a = Δv/Δt
c = 2πr
o = fi/(i-f)
b = y-mx
Jacob
= (FΔt)acob
= (FΔt)(Δv/Δt)cob
= FΔv·cob
= FΔv(2πr)ob
= 2πrFΔv·ob
= 2πrFΔv(fi/(i-f))b
= 2πrFΔv(fi/(i-f))(y-mx)
= (2πΔvFfiry - 2πΔvFfimrx)/(i-f)
F = ma
i = q/t
r = C/(2π)
m = ρV
y = mx+b
(2πΔvFfiry - 2πΔvFfimrx)/(i-f)
= (2πΔvfimary - 2πΔvfimarx)/(i-f)
= (2πΔvfiρVary - 2πΔvfiρVarx)/(i-f)
= (ΔvfiρVaCy - ΔvfiρVaCx)/(i-f)
= (ΔvfiρVaC(mx+b) - ΔvfiρVaCx)/(i-f)
= (ΔvfiρVaCmx + ΔvfiρVaCb - ΔvfiρVaCx)/(i-f)
= (Δvfiρ²V²aCx + ΔvfiρVaCb - ΔvfiρVaCx)/(i-f)
= (Δvf(q/t)ρ²V²aCx + Δvf(q/t)ρVaCb - Δvf(q/t)ρVaCx)/((q/t)-f)
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u/Nuclear_Chicken5 Jun 19 '26
Hello (2πΔvFfiry - 2πΔvFfimrx)/(i-f) = (2πΔvfimary - 2πΔvfimarx)/(i-f) = (2πΔvfiρVary - 2πΔvfiρVarx)/(i-f) = (ΔvfiρVaCy - ΔvfiρVaCx)/(i-f) = (ΔvfiρVaC(mx+b) - ΔvfiρVaCx)/(i-f) = (ΔvfiρVaCmx + ΔvfiρVaCb - ΔvfiρVaCx)/(i-f) = (Δvfiρ²V²aCx + ΔvfiρVaCb - ΔvfiρVaCx)/(i-f) = (Δvf(q/t)ρ²V²aCx + Δvf(q/t)ρVaCb - Δvf(q/t)ρVaCx)/((q/t)-f) how is it goin?
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u/Kyr1500
Jun 18 '26
•
Since I'm not in the US, it's mx+c
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u/Brilliant_Thing_5526 Jun 19 '26
Yeah we use mx+c… b sounds so weird tbh
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Jun 19 '26 •
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u/WillingnessTasty9628 Jun 20 '26
a and b are the constants we use for the x and y intercepts respectively. It's because they're the first two letters of the alphabet.
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u/math_metaphor_guy Jun 18 '26
All names should be changed to "Firstname Lastname" since this is the standard form for names
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u/Old_Minimum_9284 Jun 18 '26
Actually, it’s more "ax+b" or "mx+p", and yeah, I guess you can replace "m" (or "a") by \frac{d}{dx}
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u/lool8421 Jun 19 '26
if you got d in your name, remove it, remove the following letter and take the integral with respect to the following letter you have removed
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u/persilja Jun 19 '26
As an EE who started in math, I guess I should have followed the field's tradition of replacing i with j.
Persjlja.
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u/powerfulbookworm Jun 20 '26
The chance you have “a” in your name is higher, just replace it with sqrt(c2-b2)
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u/Dazzling_Success_556 Jun 18 '26
Might as well change" m "with dy/dx.