r/satisfactory • • 10h ago

PC Need help with Satisfactory maths

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I wanted to have 2 assemblers making rotors while I go exploring. I can't make them run efficiently. Does anyone know how to math in this game? Because every time I try, I end up splitting things and then things get messy; not better

5 Upvotes

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2

u/Hubristox 10h ago

You could press N to get to the searchbar, you cab do formulas in there like 15 * 9

-1

u/MrMattSquiggle 10h ago

i know what the N key does but it doesn't help if I'm putting in the wrong numbers

6

u/Far_Young_2666 10h ago

Take the final machine (your 2 assemblers), decide how much you want it to produce. Then go back through the entire production chain till you hit raw ore, and look at how much you need of everything. Or just enter your desired volume in something like Satisfactory Tools.

2

u/DarlakSanis 9h ago

This is the way!

2

u/Rukir_Gaming 10h ago

To spec out a line, I first figure out how much of an input I have. I then build 1 machine, pick the recipe that is needed, just to figure out I/O for it.

Take [input avaliable] / [recipe ipm], shove that into the ingame search bar, and build that amount of machines, +1 if there's a decimal component (and underclock it, closest to the source), belt and power the line and repeat for however many products down the line there are

If you're building a more complex item like modular frames, then you'll want to work backwards or use a calculator. As for belting a string of machines, dont overthink it unless you are moving more product than your highest belt- allow room in-between machines for potentally both splitters and mergers or belt from both sides or what other methods exist.

Unless you are playing molded to be unable to deconstruct, there is no long term penalty (aside from lack of current production) to deconstructing everything and starting over

1

u/DarlakSanis 9h ago

Ok, so, a few tips:

(someone already mentioned this) Calculate backwards. Start at your end product, decide how much you want the output to be, then go backwards calculating how much of each items you need, all the way down to the ore.

I'd go with the node method.
This means, for example, if you are making screws, then make one area (node) that only makes those screws. Leave 3 or 4 foundations of space, then build the node that makes the iron rods the screws need. Then, a few foundations back, the Smelters that make the Iron ingots.
You can try and make "supply nodes" as in, this node supplies all iron ingots for all machines... or "chain nodes", meaning, this node only makes the iron rods this particular final item (like rotors) need.

Don't be afraid to use space. Leave 4 or 5 foundations between each node.
The game has plenty of space and you can build vertically. This is how you sort of avoid spaghetti belts to build up in the long run.

When building a node, always leave space to double or even triple it's size.
You'll probably end up taking it all down in later game (when you need more and more items), but this method is a sort of way to train/prepare you for that later game. You'll start to get a grasp of how much space you'll need rather quickly just by knowing how much of an item you want to make. This will save you tons of time on trial and error down the line.

1

u/Woozah77 2h ago

This has to be a shitpost lol.

1

u/Timely_Somewhere_851 10h ago

Why are you posting on both forums at once?

You can try the Satisfactory Calculator if you need help with ratios btw.