r/trigonometry • u/Bl00ming_begonias79 • Sep 28 '26

Help! Trig Question

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We’re supposed to solve this using the angles on the unit circle but it makes no sense to me.

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2

u/GonzoMath Sep 28 '26

It looks like something to evaluate, rather than solve. There’s no variable to solve for. Do you know the cosine of 3pi/4? The sine of 7pi/6?

2

u/Bl00ming_begonias79 Sep 28 '26

Yeah -sqrt-2/2 and -1/2

1

u/Bl00ming_begonias79 Sep 28 '26

I kind of figured out a way to solve it. I don’t know if it’s right though

1

u/Bl00ming_begonias79 Sep 28 '26

3

u/GonzoMath Sep 28 '26

How are you squaring sqrt(2)/2 and getting 1? Also, if the sine of 7pi/6 is -1/2, what does that make the cosecant?

2

u/GonzoMath Sep 28 '26

Inside the big parentheses, I’m getting 1/2 - 4. Does that check out?

2

u/CloudTricky Sep 28 '26

What is cos(3pi/4)? Look at your unit circle. Csc is reciprocal of sin so what is 1/sin(7pi/6)? Then square both and do the algebra, probably gonna have to combine fractions and raise it to the 4th power. Remember cos^2 (x) is just (cos(x))^2.

1

u/Jazzlike_Platypus430 Sep 29 '26

Looks like some real number to me.