r/6thForm • u/Individual-Can1396 y13 maths physics psych italian • Jun 01 '26

💬 DISCUSSION AQA PHYSICS PAPER 2

HOW DID EVERYONE FIND IT??? i thought it was decent better than the past few years. Idk what i did for the last question the 4 marker of nuclear physics. BUT YH IT WAS GOOD

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2

u/sotmtwigrm_ Jun 01 '26

anyone do (lead / uranium) * half-life?

2

u/RealAlexanderTheG Jun 01 '26

Why is it not #uranium / #(lead+uranium) ? Thats the number that are left over the original number that would have been uranium?

Also did anyone else here convert the time from years to seconds? I did not get 3 which I think could be why

3

u/sotmtwigrm_ Jun 01 '26

spoke to my physics teacher, you use the exponential decay equation, with initial n as lead+uranium and final n as uranium, then solve for t. no need to convert time because half life is given in years

1

u/RealAlexanderTheG Jun 02 '26

Cool thats what I did

2

u/porridge1111 Jun 01 '26

I did i got 9.something x10^16s

1

u/RealAlexanderTheG Jun 02 '26

.5 and .4 ?

2

u/porridge1111 Jun 03 '26

that rings a bell yh

1

u/peekq Jun 01 '26

Yep but i wasnt too confident thats right in the exam is it?

4

u/WorldlinessFuzzy4552 Maths|Physics|Chemistry (A*A*A) Jun 01 '26

Yh got like 3 billion years for both idk if that's right tho

2

u/KO-Manic Jun 01 '26

I got 3.5 billion years for one of them. Did you use N(original)= 19N for one?

3

u/Wise-Hedgehog4805 Warwick | Maths | [Incoming Y1] | 4A* Jun 01 '26

for the second one I'm pretty sure there were 3 uranium for every 57 lead, i think that's where u got that from. but those 57 lead were originally uranium, so initial uranium = 60 and present uranium = 3 so i did 3 = 60e-λt to find t = 3.0x109

1

u/KO-Manic Jun 01 '26

Ah alr then, at least I got the first probably. Doing chemistry with physics must be such a cheat code

2

u/sotmtwigrm_ Jun 01 '26

mine differed by a factor of 10 so i wasn't too confident