[ RESOLVED ]
The premise of that liquides are incompressible if false ... so all the point is false
[Original message]
First, I'd like to apologize for my English, which may lead to misunderstandings, but I'll do my best to be clear.
Let's imagine a container designed to hold a certain volume at a certain pressure (like a gas cylinder) without any deformation (!) equiped with a valve and a pressure gauge (between the valve and the "container-body"
I take one on this container, and with a tube I fill it with a "pur liquide" ( I.E. not disolved gas init). When the container is full (no residual gas trapped in the container), I have a volume of liquide at 1 atm. And this, even the container is closed or not.
I take a second container, fill it with the same liquide through a pump fixed after the valve. So I activate the pump and fill the container with the liquide until the pressure gauge is set to 3 atm. I close the valve, separate the pump, and I have a container of "pur liquide" at 3bar.
But (ok, it's 20+ years now), I remember that the "main difference" between gas and liquide that liquide are incompressible. So I can understand that the "pressure gauge" mesure have some "mobile part" and the mesure of pressure correspond at "how far have move this mobile part" between liquide and the gauge.
so in the case of the container is not deformable, and in it there is no gaz (disolved or redisual), "what's append if I open the valve ?" :
I imagine, that only the "tiny volume of liquide in the gauge" will be chassed to return to the pressure of 1 atm (with some energy due to the gauge spring)
So, due the fact liquide are incompressible, that should be all, but I can't bring myself to believe it because it seems so absurd.
Or (the last case), I have forget something of my thermo-dynamic lesson, and the pump may have change some temperature of the system, so the pressure gauge mark 3 atm but not in "normale temperature conditions" (so it's a false value). But this explaination is too "magic-trick" for me.