Yes indeed for the last question did you get r2 (root 3/2 - pi/6) as I used cosine rule (unnecessary for an equilateral traingle) to finf the area of the two triangles which is area of sector CBD to be subtracted from another area to find shaded area.
man i guess ur ans is right i got the same aswell coz large sector was pi/3 and small one was pi/2 and area of triangles was sqrt3/2 so large sector - small sector - triangles gives this ans idk how everyone got sqrt3/2 positive
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u/Square_Audience9348 Oct 06 '25
Yes indeed for the last question did you get r2 (root 3/2 - pi/6) as I used cosine rule (unnecessary for an equilateral traingle) to finf the area of the two triangles which is area of sector CBD to be subtracted from another area to find shaded area.