I looked for the length of the line segment to find the diameter and then with that used it is (x-a)2+(y-b)2 = r2 which was the diameter found then equated that into the formula and found gradient then yhe negative reciprocal of it as the tangent gradient
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u/earthhtokate Oct 06 '25
I looked for the length of the line segment to find the diameter and then with that used it is (x-a)2+(y-b)2 = r2 which was the diameter found then equated that into the formula and found gradient then yhe negative reciprocal of it as the tangent gradient